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8x^2+12x-260=0
a = 8; b = 12; c = -260;
Δ = b2-4ac
Δ = 122-4·8·(-260)
Δ = 8464
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{8464}=92$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-92}{2*8}=\frac{-104}{16} =-6+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+92}{2*8}=\frac{80}{16} =5 $
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